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Septembers Oct 16, 2015 via Android
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c742435 Oct 16, 2015
byte = bits[0] * 128 + bits[1] * 64.....
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zhujinliang Oct 16, 2015
_byte = 0;
for i = 0; i < 8; i++ { _byte = _byte << 1 | bits[i]; } |
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weiceshi Oct 16, 2015
int i = 0;
byte b = (byte)bits.Select(x=>(x?1:0)<<i++).Sum(); |
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adexbn Oct 16, 2015
那啥，打字时瞄了一眼，把标题看成了有没有好的算命方法，对不起
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hitmanx Oct 16, 2015
@zhujinliang +1
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adfreedom Oct 16, 2015
@zhujinliang +1
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zealot0630 Oct 16, 2015
std::bitset
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ryd994 Oct 16, 2015 via Android
试试用 union{
bool[8]; unsigned char; } |
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