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zungmou
V2EX  ›  Python

以下迭代如何改为函数式?

  •  
  •   zungmou · Mar 8, 2017 · 2653 views
    This topic created in 3377 days ago, the information mentioned may be changed or developed.

    Python 代码

    def parse(self, data):
        tmp = data
        # funcs is a callable function iterator
        for func in funcs:
            tmp = func(tmp)
        return tmp
    
    5 replies    2017-03-08 21:13:51 +08:00
    yeyuexia
        1
    yeyuexia  
       Mar 8, 2017   ❤️ 1
    reduce(lamda x, y: y(x), funcs, data)
    staticor
        2
    staticor  
       Mar 8, 2017
    递归实现 判断 funcs
    eccstartup
        3
    eccstartup  
       Mar 8, 2017
    funs = [(+1),(*2),(subtract 3)]
    f = foldr (flip (.)) id funs
    f 1
    zungmou
        4
    zungmou  
    OP
       Mar 8, 2017
    @eccstartup 您这不是 Python 代码呀
    zhzy0077
        5
    zhzy0077  
       Mar 8, 2017 via Android   ❤️ 1
    (fold-left (λ (tmp, func) (func tmp)) data funcs)
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