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songdg
V2EX  ›  Python

请教如何拆分数组

  •  
  •   songdg · Dec 21, 2018 · 2398 views
    This topic created in 2711 days ago, the information mentioned may be changed or developed.
    array([[135501,40], [135515, 10], [135545,20],[135553,30], [135558, 50], [135605,40], [135625, 18], [135655,60],[135659,10], [135700,70], [135705, 90, [135713,60],[135723,30], [135738, 20],[135745, 90, [135749,60],[135752,30], [135757, 20],[135758, 50]])
    数组的第一列为时间(时分秒),我想根据分钟把数组拆分成几个数组。
    3 replies    2018-12-22 16:52:13 +08:00
    wssy921
        1
    wssy921  
       Dec 21, 2018
    数组好好的,干嘛要拆他
    ruoyu0088
        2
    ruoyu0088  
       Dec 21, 2018   ❤️ 1
    import numpy as np

    #a = ...

    loc = np.where(np.diff(a[:, 0] // 100))[0] + 1

    for arr in np.split(a, loc):

    print(arr)
    songdg
        3
    songdg  
    OP
       Dec 22, 2018
    @ruoyu0088 谢谢帮助。
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