求大佬一段代码， PHP 如何处理这类数组的去重计数？

This topic created in 1233 days ago, the information mentioned may be changed or developed.

原数组


Array
(
    [0] => Array
        (
            [0] => 1
            [1] => 2
            [2] => 
        )

    [1] => Array
        (
            [0] => 2
            [1] => 
        )

    [2] => Array
        (
            [0] => 2
            [1] => 
        )

    [3] => Array
        (
            [0] => 2
            [1] => 4
            [2] => 
        )

    [4] => Array
        (
            [0] => 1
            [1] => 2
            [2] => 3
            [3] => 
        )

    [5] => Array
        (
            [0] => 2
            [1] => 3
            [2] => 
        )

)

处理后的数组

Array
(
    [0] => Array
        (
            [counts] => 2
            [name] => 1
        )

    [1] => Array
        (
            [counts] => 6
            [name] => 2
        )

    [2] => Array
        (
            [counts] => 2
            [name] => 3
        )

    [3] => Array
        (
            [counts] => 1
            [name] => 4
        )

)

8 replies • 2023-01-29 01:47:41 +08:00

sadfQED2

Jan 28, 2023 via Android

写个递归函数处理？

TOTOP

Jan 28, 2023

@sadfQED2 有思路不会写[doge]

admpubcom

Jan 28, 2023 via iPhone

使用一个临时的中间数组来统计，用要统计的值来作为数组的 key ，统计数作为数组的值

zakokun

Jan 28, 2023

循环第一个数组，放到中间数组，中间数组的 key 是值，value 是出现次数。再循环这个中间数组，生成最终结果

shengtao

Jan 28, 2023

```php
$arr = [];
foreach ($a as $v) {
$arr = array_merge($arr, $v);
}

// 如果需要过滤 null 值的话
$arr = array_filter($arr, function ($item) {
return !is_null($item);
});

$c = array_count_values($arr);

$result = [];
foreach ($c as $key => $value) {
$result[] = [
'name' => $key,
'counts' => $value,
];
}
var_dump($result);
```

phpdever

Jan 28, 2023

https://gist.github.com/phpdever/ce203fea48afebb17d47e5d5da98d785

mumu

Jan 29, 2023

先合并数组，array_unique 去重，然后，substr_count

mumu

Jan 29, 2023

忘记说了，去重之前，join 一下，生成 string ，最后在 substr_count 获取 count